How can I build a table in several columns so that the numbering is automatic and the values in the table header are not numbered. You need to get a table in accordance with the figure
\documentclass[a4paper,12pt]{article}
\usepackage{cmap}
\usepackage[T2A]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[english,russian]{babel}
\usepackage{caption}
\usepackage{multirow}
\usepackage{array,etoolbox}
\usepackage{tikz}
\usepackage{siunitx}
\usepackage{nicematrix}
\usetikzlibrary{calc,angles,positioning,intersections,quotes,decorations.markings}
\usepackage{tkz-euclide}
\usepackage{pgfplots}
\pgfplotsset{compat=newest}
\usepackage[skip=1ex]{subcaption}
\usepackage{multicol}
\begin{document}
\newcounter{rownum}
\setcounter{rownum}{-1}
\newcommand{\Rownum}{\stepcounter{rownum} \ifnum\value{rownum}>0\relax\arabic{rownum}\fi }
\begin{table}[ht]
\centering
\ExplSyntaxOn
\NewDocumentCommand \BackgroundColors { }
{
\begin{tikzpicture}
\begin{scope}
\clip [rounded~corners] (1-|1) rectangle (last-|last) ;
\fill [gray!40] (1-|1) rectangle (2-|last) ;
\foreach \i in {3,5,7,...,\arabic{iRow}}
{ \fill [gray!20] (\i-|1) rectangle (\int_eval:n{\i+1}-|last) ; }
\end{scope}
\draw [rounded~corners,gray!80] (1-|1) rectangle (last-|last) ;
\end{tikzpicture}
}
\ExplSyntaxOff
\renewcommand{\arraystretch}{1.5}
\begin{multicols}{2}
\begin{NiceTabular}{>{\Rownum}cc}
\CodeBefore
\BackgroundColors
\Body
\RowStyle[bold]{}
{\textnumero} & {F, MHz} \\
& 433,075 \\
& 433,100 \\
& 433,125 \\
& 433,155 \\
& 433,175 \\
& 433,200 \\
& 433,225 \\
& 433,255 \\
\end{NiceTabular}
\columnbreak
\begin{NiceTabular}{>{\Rownum}cc}
\CodeBefore
\BackgroundColors
\Body
\RowStyle[bold]{}
{\textnumero} & {F, MHz} \\
& 433,075 \\
& 433,100 \\
& 433,125 \\
& 433,155 \\
& 434 \\
& 435 \\
& 436 \\
& 437 \\
\end{NiceTabular}
\end{multicols}
\end{table}
\end{document}
\setcounter{rownum}{-1}
and then:\newcommand{\Rownum}{\stepcounter{rownum} \ifnum\value{rownum}>0\relax\arabic{rownum}\fi }
.