How to move current arrow away from the component?

Question

This is what my outcome is and cannot seem to figure hw to move the arrow of the inductor away from the inductor

\begin{circuitikz}[american, straight voltages]
\draw (0,0)
    to [american voltage source, v=$V_P$, invert, voltage shift=1] (0,4) %Input voltage  Vp
    to [R=$R_p$] (3,4)
    to [R=$R_L$] (6,4)
    to [L, l_=$L$, v^<=$v_L$, i=$i_L$, voltage shift=1.5] (7,4)
    
    to [Tnigbt,bodydiode] (11,4)
    to [short] (13,4)
    to [american voltage source, v^<=$V_{out}$, voltage shift=1] (13,0)
    to [short] (0,0)
    
    
    
    (3,4) to [R=$R_Ci$] (3,1.5)
    to [C, l_=$C_i$, v^<=$v_{Ci}$] (3,0)
    
    (7.75,4) to [Tnigbt,bodydiode, invert] (7.75,0)
    
    (10.5,4) to [R=$R_Co$] (10.5,1.5)
    to [C, l_=$C_o$, v^<=$v_{Co}$] (10.5,0)
    
    (11,5) node[align=center]{$G_2$}
    ;
\end{circuitikz}

Answer 1

The inductor needs more space.

\documentclass{article}
\usepackage{circuitikz}

\begin{document}    

\begin{circuitikz}[american, straight voltages]
    \draw (0,0)
    to [american voltage source, v=$V_P$, invert, voltage shift=1] (0,4) %Input voltage  Vp
    to [R=$R_p$] (2,4)
    to [R=$R_L$] (4,4)
    to [L, l_=$L$, v^<=$v_L$, i=$i_L$, voltage shift=1.5] (7,4)
    
    to [Tnigbt,bodydiode] (10,4)
    to [short] (12,4)
    to [american voltage source, v^<=$V_{out}$, voltage shift=1] (12,0)
    to [short] (0,0)
        
    (2.0,4) to [R=$R_Ci$] (2.0,1.5)
    to [C, l_=$C_i$, v^<=$v_{Ci}$] (2.0,0)
    
    (7.2,4) to [Tnigbt,bodydiode, invert] (7.2,0)
    
    (10.0,4) to [R=$R_Co$] (10.0,1.5)
    to [C, l_=$C_o$, v^<=$v_{Co}$] (10.0,0)
    
    (11,5) node[align=center]{$G_2$}
    ;
\end{circuitikz}    

\end{document}

Add \draw[help lines,red,thin,dotted] (-1,0) grid (14,5);

to display the helper lines.