How can I make the arrow and label red without changing the inductor color and position?

Question

From Zarko's answer to my preivous question by adding [short,...] I can insert a current arrow on any wire section and can specify color of both label and the arrow. That is great and satisfy in most cases.

\draw  (0,0) node[ocirc,scale=2] {} to [short, i>^= $I_L$, color=red, bipole current append style={color=red}] ++(0.5,0) to [cute inductor,
,bipole current append style={color=red}] ++( 1.5,0)  node[ocirc,scale=2]{} ;

Now if I don't use [short,..] I could do it like this but this would make the inductor red as well.

\draw  (0,-1) node[ocirc,scale=2] {}  to [cute inductor, i>^= $I_L$, color=red
,bipole current append style={color=red}] ++(2,0)  node[ocirc,scale=2]{} ;

Assuming that I want to place the inductor in the middle between two ends as in the second case, how can I do that? If I use [short,..] with very small distance like (0,0) [short,..] ++(0.1,0) it would place the arrow very close to the left terminal which is not desired.

The main reason for not using [short,...] is that I made a lot of circuits with TikZ and now if I change that then I would have to change all things as many of them depends on the inductor coordinate. Also in some cases, the built-in current arrow is good and you don't want to add [short] as it would probably require more space or make the inductor asymmetric as in the first image.

\documentclass[margin=3mm]{standalone}
\usepackage[american,siunitx,RPvoltages]{circuitikz}

\begin{document}


\begin{circuitikz}

\draw  (0,0) node[ocirc,scale=2] {} to [short, i>^= $I_L$, color=red, bipole current append style={color=red}] ++(0.5,0) to [cute inductor,
,bipole current append style={color=red}] ++( 1.5,0)  node[ocirc,scale=2]{} ;

\draw  (0,-1) node[ocirc,scale=2] {}  to [cute inductor, i>^= $I_L$, color=red
,bipole current append style={color=red}] ++(2,0)  node[ocirc,scale=2]{} ;
\end{circuitikz}


\end{document}

Answer 1

I must confess, that question is not enterally clear to me. So, I guess, that you after:

\documentclass[margin=3mm]{standalone}
\usepackage[american,siunitx]{circuitikz}

\begin{document}

\begin{circuitikz}
\ctikzset{bipoles/capacitor/width/.initial=.075,
          current arrow scale=8,
          bipole current append style={color=red}}

\draw   (0,0)   node[ocirc] {}
                to [short, i=$I_{C}$, color=red]    ++ (0.75,0)
                to [cute inductor, v^=$V_L$, 
                    inductors/scale=0.8, color=red] ++ (1.5,0)
                node[ocirc] {};
\end{circuitikz}

\end{document}

Edit:
One try more, but I'm still not sure what you after ...

\documentclass[margin=3mm]{standalone}
\usepackage[american,siunitx]{circuitikz}

\begin{document}

\begin{circuitikz}
\ctikzset{bipoles/capacitor/width/.initial=.075,
          %current arrow scale=8,
          bipole current append style={color=red}}

\draw   (0,0)   node[ocirc] {}
                to [short, i=$I_{C}$, color=red]    ++ (0.55,0)
        (0,0)   to [cute inductor] ++ (2,0)
                node[ocirc] {};
\end{circuitikz}

\end{document}

Answer 2

Color is hard (especially in circuitikz). I was quite surprised that the solution offered for the first case works; it's not deliberate because, basically, it is very difficult to infer inside the shapes, which is the drawing color. Remember that the color is a path-global property, that red and color=red is not the same thing, and that rules are, well, difficult; the next example is plain TikZ, no circuitikz involved:

\documentclass[border=10pt]{standalone}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}[]
    \draw [thick, color=red] (0,0.2) -- ++(1,0) [color=blue] -- ++(1,0);
    \draw [thick, color=red] (0,0) -- ++(1,0) {[color=blue] -- ++(1,0)};
\end{tikzpicture}
\end{document}

...and additional nodes (like the current arrows or the labels) are added after the path is finished, so sometimes you really do not know which color should be acting now.

So, basically, the safe thing is to use only class colors (when they are provided) or use different paths. To help this situation, I added the "advanced voltage and current" (which should be called "by hand voltage and current", maybe); I would write your circuit like the following (I am throwing in a trick for big poles... had no time previously).

\documentclass[margin=3mm]{standalone}
\usepackage[american,siunitx,RPvoltages]{circuitikz}

\begin{document}

% define big poles...
\tikzset{% this definition is at tikz level, because
    % it will be used with a `node[... ]` element
    % the "nodes width" will be kept local
        bigO/.style={ocirc, circuitikz/nodes width=0.1},
    }
\ctikzset{% define new poles style
    O-/.style={bipole nodes={bigO}{none}},
    O-O/.style={bipole nodes={bigO}{bigO}},
    -O/.style={bipole nodes={none}{bigO}},
    !i/.style={no i symbols},
}
\newcommand{\iarronly}[2][red]{% name
\node [currarrow, color=#1, anchor=center,
rotate=\ctikzgetdirection{#2-Iarrow}] at (#2-Ipos) {};
}
\begin{circuitikz}
    % you need a quite new latex for mathcolor...
    \draw  (0,1) to[cute inductor, i>^=$\mathcolor{red}{I_L}$,
    name=LL, !i, O-O] ++(2,0) to[cute open switch] ++ (2,0);
    \iarronly{LL}% red is the default

    \draw  (0,0) to[cute inductor, i>^={\color{blue}$I_L$}, 
    name=LL1, !i, O-O] ++(2,0);
    \iarronly[blue]{LL1}
\end{circuitikz}

\end{document}