I have not been able to figure out the alignment issue I am having. You can see the numbers are not quite aligned, most likely due to the display of the integrals. Can anyone help me figure out how to align these?

\documentclass[12pt,letterpaper]{article}
\usepackage{fullpage}
\usepackage[top=1in, bottom=1.5in, left=1in, right=1in]{geometry}
\usepackage{amsmath,amsthm,amsfonts,amssymb,amscd}
\usepackage{lastpage}
\usepackage{fancyhdr}
\usepackage{parskip}
\usepackage{multicol}

% Edit these as appropriate
\newcommand\course{AP Calculus AB}

\pagestyle{fancyplain}

\lfoot{Differentiation and Integration}
\chead{Cumulative Review \\ Differentiation and Integration}
\lfoot{AP Calculus AB}
\cfoot{Flint Hill}
\rfoot{\small\thepage}
label-width=12pt,
item-indent=3em,
before-skip=0pt,
after-skip=0pt,
after-item-skip=0pt,
}
\begin{document}
\begin{multicols}{2}
\task[1. ] \;  $$f\big(x\big)=\big(2x+3\big)^3\cdot \cos x$$, find $$f^\prime$$ \\
\task[2. ] \;  $$\displaystyle{\int \sin\big(4x\big)\; dx=}$$ \\
\task[3. ] \; If $$f\big(x\big)=e^{2x}$$, then $$f^\prime\big(x\big)$$ \\
\task[4. ] \; $$\displaystyle{\int\big(x^5-\sin x\big)\; dx=}$$ \\
\task[5. ] \; $$x^3+2xy+2y^2=90$$, find $$dy/dx$$ \\
\task[6. ] \; $$f\big(x\big)=\sin^4\big(x^3\big)$$ find $$f^\prime\big(x\big)$$ \\
\task[7. ] \; $$\displaystyle{\int\cos^5\big(x\big)\sin\big(x\big)\; dx=}$$ \\
\task[8. ] \; $$y=\big(x^2-3x\big)^6$$ find $$y^\prime$$ \\
\task[9. ] \; $$y=\ln|\sin x|$$ find $$y^\prime$$ \\
\task[10. ] \; $$\displaystyle{\int 4x\cos\big(x^2\big)\;dx=}$$ \\
\task[11. ]  \; $$f\big(x\big)=e^{-x/2}$$ find $$f^\prime\big(x\big)$$ \\
\task[12. ]\;   $$y=\dfrac{x}{\sqrt{1-x}}$$ find $$y^\prime$$ \\
\task[13. ] \; $$\displaystyle{\int\big(x+2\big)\big(x^2+4x+11\big)\; dx}$$ \\
\task[14. ] \; $$y=\dfrac{8}{1+\cot x}$$, find $$y^\prime$$ \\
\task[15. ] \; $$\displaystyle{\int \sqrt[5]{3-5x}\; dx}$$ \\
\task[16.] \; $$\tan\big(x+y\big)=5x$$ find $$dy/dx$$ \\
\task[17. ] \; $$\displaystyle{\int 5\; dx}$$ \\
\task[18. ] \; $$y=\ln\sqrt{x^2-4}$$ find $$y^\prime$$ \\
\task[19. ] \; $$f\big(x\big)=x^2e^x$$ find $$f^\prime\big(x\big)$$ \\
\task[20. ] \; $$\displaystyle{\int x^3\big(1-x^2\big)\; dx}$$ \\
\task[21. ] \; $$f\big(x\big)=e^{\sin x}$$ find $$f^\prime\big(x\big)$$ \\
\task[22. ] \; $$\displaystyle{\int\dfrac{1}{x^2}\; dx=}$$\\
\task[23. ] \;  $$y=\sin^{-1}\big(7x\big)$$, find $$y^\prime$$ \\
\task[24. ] \;  $$\displaystyle{\int 4\sec x\tan x\; dx=}$$\\
\task[25. ] \;  $$f\big(x\big)=\ln\big|2x^3-5\big|$$, find $$f^\prime\big(x\big)$$ \\
\task[26. ]  \; $$\displaystyle{\int\dfrac{1}{\sqrt[3]{x^{11}}}\; dx}=$$\\
\task[27. ]  \; $$\displaystyle{\int 2x\big(x^2+1\big)^2\; dx=}$$\\
\task[28. ]  \; $$f\big(x\big)=\dfrac{1}{4}\sin^2\big(2x\big)$$ find $$f^\prime\big(x\big)$$\\
\task[29. ]  \; $$f\big(x\big)=\dfrac{e^x}{x^3}$$, find $$f^\prime\big(x\big)$$ \\
\task[30. ] \; $$f\big(x\big)=5e^{2-x}$$ find $$f^\prime\big(x\big)$$ \\
\task[31. ] \; $$\displaystyle{\int x\big(60x^3-1\big)\; dx=}$$ \\
\task[32. ] \; $$f\big(x\big)=x^3\tan\big(5x\big)$$ find $$f^\prime\big(x\big)$$ \\
\task[33. ] \; $$\displaystyle{\int\Bigg(x^2-\dfrac{1}{x^3}\Bigg)\; dx=}$$\\
\task[34. ] \; $$15\sec x\tan x\; dx=$$ \\
\task[35. ]\;$$f\big(x\big)=x\sqrt{x^3+2}$$ find $$f^\prime\big(x\big)$$ \\
\task[36. ] \; $$y=\tan^{-1}\sqrt{x}$$ find $$y^\prime$$ \\
\task[37. ] \; $$\displaystyle{\big(x+1\big)^2\; dx=}$$ \\
\task[38. ] \; $$f\big(x\big)=\tan^2\big(5x\big)$$ find $$f^\prime\big(x\big)$$ \\
\end{multicols}
\end{document}


• If you have on left column an integral on a line, it would probably help if you have on the right on the same line an integral, and same for fractions. Some tips for better code: replace ^\prime by ', \big( and \Bigg( by \left(, \big) and \Bigg) by \right), suppress all [xx. ], and replace \begin{task} by \begin{task}[label=\arabic*., label-align=right, label-offset=0.67em] and increase the label-width dimension to something like 16pt. Suppress all \; right after \task. Commented Jan 29, 2023 at 0:37
• Thank you. I changed the code with your suggestions. Still off with the numbers and columns. Commented Jan 29, 2023 at 1:23
• I'm not sure why you'd want the numbering to go top-to-bottom and left-to-right rather than the more natural left-to-right and top-to-bottom. Commented Jan 29, 2023 at 11:21

Since your problem stems from the integral signs, you can add \vphantom{$\displaystyle$ to every item.

\documentclass[12pt,letterpaper]{article}
%\usepackage{fullpage}
\usepackage[
top=1in,
bottom=1.5in,
left=1in,
right=1in,
]{geometry}
\usepackage{amsmath,amsthm,amsfonts,amssymb,amscd}
\usepackage{lastpage}
\usepackage{fancyhdr}
%\usepackage{parskip}
\usepackage{multicol}

% Edit these as appropriate
\newcommand\course{AP Calculus AB}

\pagestyle{fancyplain}

\lfoot{Differentiation and Integration}
\chead{Cumulative Review \\ Differentiation and Integration}
\lfoot{AP Calculus AB}
\cfoot{Flint Hill}
\rfoot{\small\thepage}

label=\arabic*.,
label-width=24pt,
item-indent=3em,
before-skip=0pt,
after-skip=0pt,
after-item-skip=12pt,
item-format={\vphantom{$\displaystyle\int$}},
}

\begin{document}

\begin{multicols}{2}
\task $$f(x)=(2x+3)^3\cdot \cos x$$, find $$f'$$
\task $$\displaystyle \int \sin(4x)\, dx=$$
\task If $$f(x)=e^{2x}$$, then $$f'(x)$$
\task $$\displaystyle \int(x^5-\sin x)\, dx=$$
\task $$x^3+2xy+2y^2=90$$, find $$dy/dx$$
\task $$f(x)=\sin^4(x^3)$$ find $$f'(x)$$
\task $$\displaystyle \int\cos^5(x)\sin(x)\, dx=$$
\task $$y=(x^2-3x)^6$$ find $$y'$$
\task $$y=\ln|\sin x|$$ find $$y'$$
\task $$\displaystyle \int 4x\cos(x^2)\,dx=$$
\task $$f(x)=e^{-x/2}$$ find $$f'(x)$$
\task $$y=\dfrac{x}{\sqrt{1-x}}$$ find $$y'$$
\task $$\displaystyle \int(x+2)(x^2+4x+11)\, dx$$
\task $$y=\dfrac{8}{1+\cot x}$$, find $$y'$$
\task $$\displaystyle \int \sqrt[5]{3-5x}\, dx$$
\task $$\tan(x+y)=5x$$ find $$dy/dx$$
\task $$\displaystyle \int 5\, dx$$
\task $$y=\ln\sqrt{x^2-4}$$ find $$y'$$
\task $$f(x)=x^2e^x$$ find $$f'(x)$$
\task $$\displaystyle \int x^3(1-x^2)\, dx$$
\task $$f(x)=e^{\sin x}$$ find $$f'(x)$$
\task $$\displaystyle \int\dfrac{1}{x^2}\, dx=$$
\task $$y=\sin^{-1}(7x)$$, find $$y'$$
\task $$\displaystyle \int 4\sec x\tan x\, dx=$$
\task $$f(x)=\ln\big|2x^3-5\big|$$, find $$f'(x)$$
\task $$\displaystyle \int\frac{1}{\sqrt[3]{x^{11}}}\, dx=$$
\task $$\displaystyle \int 2x(x^2+1)^2\, dx=$$
\task $$f(x)=\dfrac{1}{4}\sin^2(2x)$$ find $$f'(x)$$
\task $$f(x)=\dfrac{e^x}{x^3}$$, find $$f'(x)$$
\task $$f(x)=5e^{2-x}$$ find $$f'(x)$$
\task $$\displaystyle \int x(60x^3-1)\, dx=$$
\task $$f(x)=x^3\tan(5x)$$ find $$f'(x)$$
\task $$\displaystyle \int\Bigl(x^2-\dfrac{1}{x^3}\Bigr)\, dx=$$
\task $$\displaystyle \int 15\sec x\tan x\, dx=$$
\task $$f(x)=x\sqrt{x^3+2}$$ find $$f'(x)$$
\task $$y=\tan^{-1}\sqrt{x}$$ find $$y'$$
\task $$\displaystyle \int(x+1)^2\, dx=$$
\task $$f(x)=\tan^2(5x)$$ find $$f'(x)$$
\end{multicols}

\end{document}


Note that I vastly simplified your code:

1. no \big is used, because parentheses are already the right size
2. ^\prime is better input as '
3. no manual numbering, as tasks is able to do it by itself
4. all \; have been removed, but replaced by \, in front of dx
5. instead of \Bigg, I used \Bigl and \Bigr (the smaller the fences, the better)
6. all \\ have been removed as useless, replaced by a fixed separation between items
7. \displaystyle doesn't take an argument

On the other hand, I see no reason for this peculiar ordering (top-to-bottom and left-to-right) instead of the more natural left-to-right and top-to-bottom.

\documentclass[12pt,letterpaper]{article}
%\usepackage{fullpage}
\usepackage[
top=1in,
bottom=1.5in,
left=1in,
right=1in,
]{geometry}
\usepackage{amsmath,amsthm,amsfonts,amssymb,amscd}
\usepackage{lastpage}
\usepackage{fancyhdr}
%\usepackage{parskip}
%\usepackage{multicol}

% Edit these as appropriate
\newcommand\course{AP Calculus AB}

\pagestyle{fancyplain}

\lfoot{Differentiation and Integration}
\chead{Cumulative Review \\ Differentiation and Integration}
\lfoot{AP Calculus AB}
\cfoot{Flint Hill}
\rfoot{\small\thepage}

label=\arabic*.,
label-width=24pt,
item-indent=3em,
before-skip=0pt,
after-skip=0pt,
after-item-skip=12pt,
item-format={\vphantom{$\displaystyle\int$}},
}

\begin{document}

\task $$f(x)=(2x+3)^3\cdot \cos x$$, find $$f'$$
\task $$\displaystyle \int \sin(4x)\, dx=$$
\task If $$f(x)=e^{2x}$$, then $$f'(x)$$
\task $$\displaystyle \int(x^5-\sin x)\, dx=$$
\task $$x^3+2xy+2y^2=90$$, find $$dy/dx$$
\task $$f(x)=\sin^4(x^3)$$ find $$f'(x)$$
\task $$\displaystyle \int\cos^5(x)\sin(x)\, dx=$$
\task $$y=(x^2-3x)^6$$ find $$y'$$
\task $$y=\ln|\sin x|$$ find $$y'$$
\task $$\displaystyle \int 4x\cos(x^2)\,dx=$$
\task $$f(x)=e^{-x/2}$$ find $$f'(x)$$
\task $$y=\dfrac{x}{\sqrt{1-x}}$$ find $$y'$$
\task $$\displaystyle \int(x+2)(x^2+4x+11)\, dx$$
\task $$y=\dfrac{8}{1+\cot x}$$, find $$y'$$
\task $$\displaystyle \int \sqrt[5]{3-5x}\, dx$$
\task $$\tan(x+y)=5x$$ find $$dy/dx$$
\task $$\displaystyle \int 5\, dx$$
\task $$y=\ln\sqrt{x^2-4}$$ find $$y'$$
\task $$f(x)=x^2e^x$$ find $$f'(x)$$
\task $$\displaystyle \int x^3(1-x^2)\, dx$$
\task $$f(x)=e^{\sin x}$$ find $$f'(x)$$
\task $$\displaystyle \int\dfrac{1}{x^2}\, dx=$$
\task $$y=\sin^{-1}(7x)$$, find $$y'$$
\task $$\displaystyle \int 4\sec x\tan x\, dx=$$
\task $$f(x)=\ln\big|2x^3-5\big|$$, find $$f'(x)$$
\task $$\displaystyle \int\frac{1}{\sqrt[3]{x^{11}}}\, dx=$$
\task $$\displaystyle \int 2x(x^2+1)^2\, dx=$$
\task $$f(x)=\dfrac{1}{4}\sin^2(2x)$$ find $$f'(x)$$
\task $$f(x)=\dfrac{e^x}{x^3}$$, find $$f'(x)$$
\task $$f(x)=5e^{2-x}$$ find $$f'(x)$$
\task $$\displaystyle \int x(60x^3-1)\, dx=$$
\task $$f(x)=x^3\tan(5x)$$ find $$f'(x)$$
\task $$\displaystyle \int\Bigl(x^2-\dfrac{1}{x^3}\Bigr)\, dx=$$
\task $$\displaystyle \int 15\sec x\tan x\, dx=$$
\task $$f(x)=x\sqrt{x^3+2}$$ find $$f'(x)$$
\task $$y=\tan^{-1}\sqrt{x}$$ find $$y'$$
\task $$\displaystyle \int(x+1)^2\, dx=$$
\task $$f(x)=\tan^2(5x)$$ find $$f'(x)$$

\end{document}


• When I first set it up it automatically used letters for "numbering" so i just added the brackets [number] to correct it. Commented Jan 30, 2023 at 10:26

Here is a code that meet your requirements :

\documentclass[12pt,letterpaper]{article}
\usepackage{fullpage}
\usepackage[top=1in, bottom=1.5in, left=1in, right=1in]{geometry}
\usepackage{amsmath,amsthm,amsfonts,amssymb,amscd}
\usepackage{lastpage}
\usepackage{fancyhdr}
\usepackage{parskip}
\usepackage{multicol}

% Edit these as appropriate
\newcommand\course{AP Calculus AB}

\pagestyle{fancyplain}

\lfoot{Differentiation and Integration}
\chead{Cumulative Review \\ Differentiation and Integration}
\lfoot{AP Calculus AB}
\cfoot{Flint Hill}
\rfoot{\small\thepage}
label-width=16pt,
item-indent=3em,
before-skip=0pt,
after-skip=0pt,
after-item-skip=0pt,
}
\begin{document}
\begin{multicols}{2}
\task  $f\left(x\right)=\left(2x+3\right)^3\cdot \cos x$, find $f'$ \\
\task  $\displaystyle{\int \sin\left(4x\right)\; dx=}$ \\
\task If $f\left(x\right)=e^{2x}$, then $f'\left(x\right)$ \\
\task $\displaystyle{\int\left(x^5-\sin x\right)\; dx=}$ \\
\task $x^3+2xy+2y^2=90$, find $dy/dx$ \\
\task $f\left(x\right)=\sin^4\left(x^3\right)$ find $f'\left(x\right)$ \\
\task $\displaystyle{\int\cos^5\left(x\right)\sin\left(x\right)\; dx=}$ \\
\task $y=\left(x^2-3x\right)^6$ find $y'$ \\
\task $y=\ln|\sin x|$ find $y'$ \\
\task $\displaystyle{\int 4x\cos\left(x^2\right)\;dx=}$ \\
\task   $f\left(x\right)=e^{-x/2}$ find $f'\left(x\right)$ \\
\task   $y=\dfrac{x}{\sqrt{1-x}}$ find $y'$ \\
\task $\displaystyle{\int\left(x+2\right)\left(x^2+4x+11\right)\; dx}$ \\
\task $y=\dfrac{8}{1+\cot x}$, find $y'$ \\
\task $\displaystyle{\int \sqrt[5]{3-5x}\; dx}$ \\
\task $\tan\left(x+y\right)=5x$ find $dy/dx$ \\
\task $y=\ln\sqrt{x^2-4}$ find $y'$ \\
\task $f\left(x\right)=x^2e^x$ find $f'\left(x\right)$ \\
\task $\displaystyle{\int 5\; dx}$ \\
\task $f\left(x\right)=e^{\sin x}$ find $f'\left(x\right)$ \\
\task $\displaystyle{\int x^3\left(1-x^2\right)\; dx}$ \\
\task  $y=\sin^{-1}\left(7x\right)$, find $y'$ \\
\task  $f\left(x\right)=\ln\left|2x^3-5\right|$, find $f'\left(x\right)$ \\
\task  $\displaystyle{\int 4\sec x\tan x\; dx=}$\\
\task $\displaystyle{\left(x+1\right)^2\; dx=}$ \\
\task $f\left(x\right)=\tan^2\left(5x\right)$ find $f'\left(x\right)$ \\
\task $\displaystyle{\int\dfrac{1}{x^2}\; dx=}$\\
\task $f\left(x\right)=5e^{2-x}$ find $f'\left(x\right)$ \\
\task  $f\left(x\right)=\dfrac{e^x}{x^3}$, find $f'\left(x\right)$ \\
\task $\displaystyle{\int x\left(60x^3-1\right)\; dx=}$ \\
\task   $f\left(x\right)=\dfrac{1}{4}\sin^2\left(2x\right)$ find $f'\left(x\right)$\\
\task  $\displaystyle{\int 2x\left(x^2+1\right)^2\; dx=}$\\
\task $15\sec x\tan x\; dx=$ \\
\task $f\left(x\right)=x\sqrt{x^3+2}$ find $f'\left(x\right)$ \\
\task $y=\tan^{-1}\sqrt{x}$ find $y'$ \\
\task  $\displaystyle{\int\dfrac{1}{\sqrt[3]{x^{11}}}\; dx}=$\\
\task $f\left(x\right)=x^3\tan\left(5x\right)$ find $f'\left(x\right)$ \\
\task $\displaystyle{\int\left(x^2-\dfrac{1}{x^3}\right)\; dx=}$\\