2

I need to draw the following scheme of equilibrium state of Fluorescein enter image description here

Using chemfig package, and here's my code for that:

\documentclass[12pt, a4paper]{article}
\usepackage{chemfig}
\begin{document}
\chemfig{
    O=[:-54]*5(-O-(-*6(-(*6(-=-(-OH)=-=))--O-(*6(=-(-OH)=-=-))--))-(*6(-=-=-=))--)
}
\end{document}

The only problem I have is I can't get rid of the bond shown in the result of the previous code, any idea?

enter image description here

2 Answers 2

4

you want this way?

I started writing the molecule by the central hexagon.

I find it easiest to start at the center and place the other parts of the molecule around the central hexagon.

\documentclass[12pt, a4paper]{article}
\usepackage{chemfig}
\begin{document}
\chemfig{*6(-O-(*6(=-(-OH)=-=))--([:84]*5(-(*6(-=-=-))--(=O)-O-))-(*6(-=-(-HO)=-))-)}
\end{document}

enter image description here

enter image description here

4
\documentclass[12pt, a4paper]{article}
\usepackage{chemfig}
\begin{document}
    \chemfig{
        O=[:-54]*5(-O-?(-[:210]*6(-=-(-HO)=-(-O-[:30]*6(=-(-OH)=-=?-))=))-(*6(-=-=-=))--)
    }
\end{document}

enter image description here

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