5

Assume I have a table with a dynamic number of rows and columns, and I want to fill the table with n elements. Assume an element has the constant length x, and I want to say make floor(linewitdth/x) columns per row so that the maximal number of elements is in a row. How would I write that in LaTeX?

3
  • LaTeX tables don't have a dynamical number of columns. The elements of the table are saved in a csv file? I think the package datatool will be the best choice. Aug 23, 2012 at 18:49
  • No, the data comes in as a string, thats the problem....
    – Twerp
    Aug 23, 2012 at 19:46
  • Counting the elements of a string is really simple. Please provide a minimal example. The elements are separated by comma? Aug 24, 2012 at 5:51

1 Answer 1

3

If your elements all have the same width x (either naturally or because you put each one in a \makebox[3cm][l]{.....} ) then you don't need a table construct or to do any arithmetic, just place them one after another in a flushleft environment and the paragraph breaker will naturally fit as many as it can on each line, and vertical alignment is automatic.

See this technique being used

building a table of images

or

enumerate in multicols

1
  • ok, this looks promisingg, last stupid question - for a given string x, how do i determine the width and put it in your formula?
    – Twerp
    Aug 24, 2012 at 9:55

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .