This could be a starting point. It uses 3d
and perspective
TikZ libraries, and I'm 'reconstructin your function (hope is the right one).
\documentclass[tikz,border=1.616mm]{standalone}
\usetikzlibrary{3d,perspective}
\begin{document}
\begin{tikzpicture}[3d view={120}{30},domain=-1:3.5,samples=1001]
\draw[canvas is xz plane at y=-1] (-2,-2) rectangle (2,2);
\draw[canvas is yz plane at x=-2] (-1,-2) rectangle (3.5,2);
\draw[canvas is xy plane at z=-2] (-2,-1) rectangle (2,3.5);
\draw[blue] plot ({exp(-2*(\x-1.25)*(\x-1.25))*cos((\x-1.25)*1140)},\x,{exp(-2*(\x-1.25)*(\x-1.25))*sin((\x-1.25)*1140)});
\draw[red] plot ({exp(-2*(\x-1.25)*(\x-1.25))*cos((\x-1.25)*1140)},\x,-2);
\draw plot (-2,\x,{exp(-2*(\x-1.25)*(\x-1.25))*sin((\x-1.25)*1140)});
\end{tikzpicture}
\end{document}

Update: another version using a \pic
for the function and its projections.
\documentclass[tikz,border=1.616mm]{standalone}
\usetikzlibrary{3d,perspective}
\tikzset
{%
pics/spiral/.style 2 args={code=%
{
\draw[pic actions] plot[domain=#1:#2,samples=1001]
({exp(-2*\x*\x)*cos(1140*\x)},\x,
{exp(-2*\x*\x)*sin(1140*\x)});
}},
}
\begin{document}
\begin{tikzpicture}[3d view={120}{30},line cap=round,line join=round]
\draw[canvas is xy plane at z=-2] (-2,-3) rectangle (2,3);
\draw[canvas is xz plane at y=-3] (-2,-2) rectangle (2,2);
\draw[canvas is yz plane at x=-2] (-3,-2) rectangle (3,2);
\begin{scope}[shift={(0,-3,0)}]
\pic[teal,y=0] {spiral={-3}{3}};
\end{scope}
\pic [red ,canvas is xy plane at z=-2] {spiral={-3}{3}};
\pic [green!50!black,canvas is zy plane at x=-2] {spiral={-3}{3}};
\pic [blue,thick] {spiral={-3}{3}};
\end{tikzpicture}
\end{document}
