TikZ / foreach: read out sequence of Unicode symbols

Question

How can I read out \char"1F0A1,...,\char"1F0DF
that means \char127137, ..., \char127199
with a foreach-loop?

I got Dimensions too large if I use the second version; and TikZ does not like hexadecimal numbers at the first version.

Does TikZ know a solution here or is that only possible with other things?

Hint: By using the font Segoe UI Symbol or DejaVu Sans this should give the unicode play card symbols:

Test-MWE with incorrect numbers:

% arara: lualatex
\documentclass[a4paper]{article}
\usepackage{tikz}
\usepackage{fontspec}
\newfontfamily\myfont{DejaVu Sans}

\begin{document}
\section{Test:}

\foreach[evaluate={  \LineBreak=(  int( mod(\n-1,13) ) },
evaluate={  \Seperator=(  \LineBreak==12 ? "." : ",~")  }
] \n in {14,...,78}{%% <--- here are not the correct numbers... 
\myfont\char"\n      \Seperator \ifnum\LineBreak=12 \\ \fi 
}%%
\end{document}

Answer 1

You may probably get away with a \foreach loop from 37 to 99, using arithmetic for printing the right glyph

\char\numexpr127100+\n\relax

Here's a different loop; note that the playing cards block has sixteen slots for each suit.

\documentclass[a4paper]{article}
\usepackage{fontspec}

\newfontfamily\cardfont{DejaVu Sans}

\ExplSyntaxOn
\NewDocumentCommand{\intstep}{m O{1} m +m}
 {% #1 = start, #2 = step, #3 = end, #4 = action
  \int_step_inline:nnnn { #1 } { #2 } { #3 } { #4 }
 }
\NewDocumentCommand{\actionmodulo}{m m +m +m}
 {% #1 = integer to test, #2 = modulo, #3 = normal action, #4 = action at multiples of #1
  \int_compare:nTF { \int_mod:nn { #1 } { #2 } == 0 } { #4 } { #3 }
 }
\ExplSyntaxOff

\newcounter{step}

\begin{document}

\intstep{"1F0A1}{"1F0DF}{%
  {\cardfont\symbol{#1}}%
  \stepcounter{step}%
  \actionmodulo{\value{step}}{16}{, }{.\par}%
}

\end{document}

You may modify the loop to discard the unwanted slots.