Consider four kinds of "arrow" symbols: 0. A horizontal line 1. A leftarrow 2. A rightarrow 3. A doublearrow

I'd like to add circles to each end of these arrows, allowing for all possible combinations of "filled" and "unfilled," for a total of sixteen combinations in total. As an example, one may consider the "spoons" offered by the MnSymbol package for reference, as in \leftspoon and \leftfilledspoon.

Any ideas as to how to achieve this?

EDIT: So to clarify, I want circles on BOTH ends of the arrows. As in O-->O.

  • Where is the arrow? Above the filled circle (more or less invisible), outwards or in the inside, ...? – Heiko Oberdiek Dec 4 '12 at 17:26

You can use \hbox to create your own arrows by appending other symbols, like this:

\def\CircleftarrowCirc{\hbox{$\circ$}\kern-1.5pt\hbox{$\leftarrow$}\kern 1.5pt\hbox{$\circ$}}

enter image description here

| improve this answer | |
  • Thanks. There needs to be a negative on the second kern, but in broad terms this is the answer I was looking for. So the fixed code reads: \def\CircleftarrowCirc{\hbox{$\circ$}\kern-1.5pt\hbox{$\leftarrow$}\kern-1.5pt\hbox{$\circ$}} – goblin Dec 4 '12 at 17:55
  • @user18921: Good that you spotted the missing negative. I had it in the original code to create the image. It somehow got lost in the copy&paste. – Mafra Dec 4 '12 at 18:07

I think the intended arrowtips are the following:


which were produced with the following code:


\def\generateFourVariants#1{% Parameter, arrow style
\foreach \left in {white, black} {
  \foreach \right in {white,black} {
    \draw[fill=\left]  (0,\y) circle (2pt);    
    \draw[fill=\right] (1,\y) circle (2pt);
    \draw[shorten <=2pt, shorten >=2pt, arrows=#1] (0,\y) -- (1, \y);

  \begin{scope}[xshift=0 cm]
  \begin{scope}[xshift=2 cm]
  \begin{scope}[xshift=4 cm]
  \begin{scope}[xshift=6 cm]


But I'm not sure if this answers the OP question...

| improve this answer | |
  • Those are indeed the symbols! – goblin Dec 4 '12 at 17:50

Package txfonts contains all these symbols, however I am counting nine variants:


\item $-$
\item $\multimapinv$, $\multimapdotinv$
\item $\multimap$, $\multimapdot$
\item $\multimapboth$,
      $\multimapdotbothA$, $\multimapdotbothB$


| improve this answer | |
  • If you look at 4, that's kind of what I'm looking for. Except I'd like the horizontal line connecting the circles to possibly end in an arrowhead. – goblin Dec 4 '12 at 17:19
  • @user18921 It's not clear to me. Perhaps you can made some ASCII art or a hand drawing? – Heiko Oberdiek Dec 4 '12 at 17:24
  • Sure! O---O, O-->O, O<--O, O<->O. That's four of them. Filling in the O's in all combinations gives the remaining twelve. – goblin Dec 4 '12 at 17:35

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