Questions tagged [sqrt]

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Height and size of \sqrt exponent [duplicate]

I want to place the n from the \sqrt[n]{\rho} command in a more visible position and make it bigger too. MWE: \sqrt[n]{\rho}
2
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0answers
59 views

Unable to write nth root [duplicate]

I would like to write the nth root, it's fairly simple as \usepackage{amsmath} \begin{equation} a = \sqrt[n]{b} \end{equation} but I get the output as Can anybody help me with this. ...
1
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1answer
28 views

Make roots fit fractions size with nccmath package

Sometimes I use the nccmath package to resize equations, mainly resizing fractions with the \mfraccommand, but I have an issue with roots that contain fractions: \documentclass[11pt]{article} \...
0
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1answer
179 views

yhmath impact on radical symbols and delimiters

In November 2014 I had an issue with this code and yhmath package: \sqrt{n+\sqrt{(n-1)+\sqrt{(n-2)+\dotsb+\sqrt{2+\sqrt{1}}}}} Depending on whether that package was being used or not (and AMS-...
3
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3answers
294 views

Integral with fraction and square root produces wrong vertical alignment

This code produces an ankward vertical alignment which involves the integral symbol and the fraction with the square root at the denominator. Why? How can I fix this? \documentclass[a4paper]{article} ...
4
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2answers
273 views

Radical with underscript

How can I make the radical end at the same level with 11...1 and 44...4 and put the underbrace below the radical? I have this: \sqrt{ \underbrace{11...1}_n\underbrace{44...4}_{2n}}
2
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2answers
68 views

“Esami” package: \randestrai and \sqrt not working together?

The \randestrai command from the "esami" package allows to define a set of elements to randomly choose within, such as a set of formulas. It works with formulas including latex commands inside, for ...
4
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2answers
652 views

How to adjust/increase the height of square root?

I defined this equation: \begin{equation} \delta {^s_i\lambda} = \begin{cases} \pm \dfrac{{^s\overline{\Delta T}}}{\sqrt[]{\delta {^s_1\bm{u}_l} \cdot \delta {^s_1\bm{u}_l} + \...
3
votes
1answer
160 views

Badly scaling closing SQRT symbol with large font sizes

I prefer the SQRT symbol with the closing downward tick, and have been using this answer to achieve the desired effect. However, when I hugely increase the font size and use fixcmex to achieve some ...
2
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2answers
504 views

differences when using inline mode and \overline and \sqrt

Can anyone help me make this square root signs in the code below, be of the same size so that they all have the same height? This is the code: \documentclass[]{book} \begin{document} $\overline{\...
3
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2answers
237 views

Same command \SQRT of MathTımeProfessional fonts (mt2pro[lite]) using baskervald(x)

From the guide MathTımeProfessional fonts mt2pro[lite] we known that in addition to the \sqrt command, which uses an extensible symbol, called \SQRT that produces individually designed root signs up ...
3
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1answer
105 views

Root index \sqrt[n]{x} misaligned with libertinust1math

I'm porting all my libertine-based documents to use \usepackage{libertinust1math} instead of \usepackage[libertine]{newtxmath} and a side effect seems to be the misalignment of the n-th root symbol: ...
2
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2answers
113 views

Round parentheses in math mode when using kpfonts

I am trying to write a simple equation that contains fractions, square roots and parentheses. However the output is ugly I'd say I tried reducing the space on the nominator using a user-defined ...
12
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3answers
703 views

smash subscript in sum

I found a solution (3rd \sqrt), but am curious as to why the \smash{} in {\sum_{\smash{ij}} (2nd \sqrt) is ignored. Notes: Related Question: Adjust vertical size of \sqrt contating terms with ...
2
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0answers
1k views

Square root symbol looking ugly

Recently I noticed that my square root symbol is looking really ugly: The square root per se is not correctly connected to the overbar. The picture above is with a small zoom factor. When I zoom in ...
0
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0answers
935 views

rendering tex: sqrt: placement of root

EDIT: after reading egreg's comment, changing from \sqrt[3]{x} to \root 3 \of{x}, to indicate using plain TeX, not LaTeX Consider $$\sqrt{x}$$ vs $$\root 3 \of{x}$$. The latter has a 'root' of 3. ...
2
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2answers
488 views

Formula too long and \split fails | contains “sqrt” (square root)

I'm quite new to LaTex and I guess I need some help. I'm writing a report and I need to display a specific formula. If I use the simple equation environment the formula gets too long for one line. ...
4
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1answer
863 views

Splitting an equation with a long square root

I want to split up a very long equation. Here is my code: \documentclass[11pt,a4paper,oneside,onecolumn,article]{memoir} \usepackage[latin1]{inputenc} \usepackage{mathtools} \usepackage{amsmath} \...
1
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1answer
195 views

Bold square root with normal argument

This is a somewhat funny question. To explain the problem of complex extensions of the principal square root, I would like to have two visibly different square root signs within the same document; for ...
6
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1answer
469 views

Adjust vertical size of \sqrt contating terms with subscript and superscript

In the second \sqrt, both the subscript and superscript are \smashed: a_{\smash{0}}^{\smash{2} Yet, the sqrt are of different sizes? How do I get the second \sqrt to be the exact vertical size of ...
1
vote
1answer
122 views

How to write braces inside \sqrt[ in here ]{sth}? [duplicate]

This is what I want to write: Apparently, the following doesn't work \sqrt[ \sqrt[\log n]{n} ]{x} The error is that the argument of \sqrt has an extra }. This seems like a bug to me. Is there a way ...
40
votes
1answer
4k views

Why do \sqrt{1} and \sqrt{-1} have different heights?

I noticed that the heights of \sqrt{1} and \sqrt{-1} are different. For instance, when they are in between \left( and \right) parentheses, I must write a character of zero-width (e.g. \sqrt{-1\...
4
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2answers
217 views

Controlling sqrts (mathptmx)

Consider this MWE \documentclass[border=10mm,varwidth=true]{standalone} \usepackage[T1]{fontenc} \usepackage{amsmath,amssymb} %\usepackage{mathptmx} \begin{document} \[ \sqrt{n+1}\sqrt{2+(n+2)^2} \] \...