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\documentclass{article} \usepackage{chemfig} \begin{document} \chemfig[bond join=true,atom sep=2em]{ \charge{[extra sep=4.5pt]0=\.}{}(-[4]*6(=-=-=-))(=^[2,,,,line cap=rect]{O\rule{2pt}{0pt}}) } \end{document}

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See chemfig manual, section Shifted double bonds: All double bonds are made up of two line segments, and these segments are drawn on either side of the imaginary line along which a single bond would be drawn. It is possible to shift a double bond so that one of the line segments lies on the imaginary line. The other segment is then shifted above or below ...

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\documentclass{article} \usepackage{graphicx} \usepackage{chemfig} \begin{document} \rotatebox{-90}{ \chemfig{ CN-[:265,,1]*6(-=-(-N*6(--*6(=-(-N*5(-(=O)-=-(=O)-))=-=)--O--))=-=) } } \end{document} Unfortunately, this code does not work correctly. \setchemfig{atom style={rotate=-90}} but node style works perfectly \chemfig[node style={...

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Just in case you want a smoother titration curve, you can check my answer using tikz. An angle of 35° works well as tangent. \documentclass[border=5pt]{standalone} \usepackage{tikz} \usetikzlibrary{intersections} \tikzset{% every pin/.style={font=\small, pin distance=5mm, inner sep=0pt}, every pin edge/.style={draw=black, line width=0.5*\...

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A straightforward solution using tkz-euclide. I decided to draw on the left, since your the curvation is really close to the right of the picture. You can adapt the code to any tangent, because the points coordinates are on them. \documentclass[tikz,border=3.14mm]{standalone} \usepackage{pgfplots,tkz-euclide} \begin{document} \begin{tikzpicture}[ultra ...

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Use the chemfig package: - draws bonds, = draws double bonds,< draws cram bonds. You will find more bonds at page 7 of the document. Number in the square brackets gives the angle of the bond. With these brackets you can give your bond optional arguments and adjust different aspects of the bond like lenght, angle, depatureof atoms.For more information see ...

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