6
\documentclass{standalone}
\usepackage{pst-eucl,pst-text,pstricks-add,pst-grad}
\usepackage{mathptmx}
\DeclareFixedFont{\RM}{T1}{ptm}{b}{n}{1.7cm}%
\begin{document}
\begin{pspicture}[showgrid=false](-5.2,-5.2)(10,5.2)
\psframe*[fillstyle=solid,linecolor=black!40,opacity=.9](-5.2,-5.2)(10,5.2)
\pscircle*[dimen=inner](0,0){5}
{%
\psset{fillstyle=solid,...
3
Here's how you can do it using TikZ: The filling will stretch over all circles as long as they're specified using a single \path (or \shade) command
\documentclass{article}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}
\shade [left color=orange!90!red, right color=green!80!orange]
\foreach \i in {-2,...,2}{
(\i*3.5ex,0) circle [radius=2....
3
Here's a TikZ solution. If you need to stick to pstricks, perhaps the same method could be applied there which is, basically, to fill the entire rectangle and to then fill 4 trapeziums to make the borders. (But the borders could be larger than the bit in the middle, of course. This is just how I thought about it.)
\documentclass[border=10pt,multi,tikz]{...
2
My code seems to be verbose but the extra code is actually to get the precise dimension and placement. It also make you more convenient to adjust the parameters.
\documentclass[pstricks,border=0pt]{standalone}
\usepackage{multido}
\usepackage{pst-grad}
\usepackage[nomessages]{fp}
\newpsstyle{A}
{
fillstyle=gradient,
gradbegin=red,
gradend=...
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